-12b^2+19b+70=0

Solution for -12b^2+19b+70=0 equation:

-12b^2+19b+70=0

a = -12; b = 19; c = +70;
Δ = b2-4ac
Δ = 192-4·(-12)·70
Δ = 3721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3721}=61$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-61}{2*-12}=\frac{-80}{-24}
=3+1/3
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+61}{2*-12}=\frac{42}{-24}
=-1+3/4
$